Java Program to Find Even and Odd Numbers from an Array

Even Odd

This Java program checks each element in an array to determine whether it is even or odd. It is a basic and commonly asked programming question in Java interviews and coding exercises.

Logic

Even Number - divisible by 2 (i.e. number % 2 == 0)
Odd Number - not divisible by 2 (i.e. number % 2 != 0)

Example: Find Even and Odd Numbers

import java.util.Scanner;

public class Main {
    public static void main(String[ ] args) {
        System.out.println("Even Odd Array Program");

        Scanner input = new Scanner(System.in);
        System.out.println("Enter Array Size");
        int size = input.nextInt();  // taking size input

        int[] arr = new int[10];     // initialize array

        System.out.println("Enter Array Values"); // taking array values
        for (int i = 0; i < size; i++) {
            arr[i] = input.nextInt();
        }

        EvenOdd(arr, size);  // calling method
    }

    public static void EvenOdd(int[] arr, int size) {
        for (int j = 0; j < size; j++) {
            if (arr[j] % 2 == 0) {
                System.out.println("Even : " + arr[j]);
            } else {
                System.out.println("Odd  : " + arr[j]);
            }
        }
    }
}

Output:

Even Odd Array Program
Enter Array Size
5
Enter Array Values
22
20
9
7
8
Even : 22  
Even : 20  
Odd  : 9  
Odd  : 7  
Even : 8

Explanation

Value	Condition	Result
22	22 % 2 == 0 - true	Even
20	20 % 2 == 0 - true	Even
9	9 % 2 == 1 - true	Odd
7	7 % 2 == 1 - true	Odd
8	8 % 2 == 0 - true	Even

Key Point

% is the modulus operator used to get the remainder.

The logic applies to both positive and negative integers.

Ideal for practicing control structures and arrays.