Java Program to Find Even and Odd Numbers from an Array

Even Odd-tutorial

This Java program checks each element in an array to determine whether it is even or odd. It is a basic and commonly asked programming question in Java interviews and coding exercises.

Logic

Even Number - divisible by 2 (i.e. number % 2 == 0)
Odd Number - not divisible by 2 (i.e. number % 2 != 0)

Example: Find Even and Odd Numbers

import java.util.Scanner;

public class Main {
    public static void main(String[ ] args) {
        System.out.println("Even Odd Array Program");

        Scanner input = new Scanner(System.in);
        System.out.println("Enter Array Size");
        int size = input.nextInt();  // taking size input

        int[] arr = new int[10];     // initialize array

        System.out.println("Enter Array Values"); // taking array values
        for (int i = 0; i < size; i++) {
            arr[i] = input.nextInt();
        }

        EvenOdd(arr, size);  // calling method
    }

    public static void EvenOdd(int[] arr, int size) {
        for (int j = 0; j < size; j++) {
            if (arr[j] % 2 == 0) {
                System.out.println("Even : " + arr[j]);
            } else {
                System.out.println("Odd  : " + arr[j]);
            }
        }
    }
}

Output:

Even Odd Array Program
Enter Array Size
5
Enter Array Values
22
20
9
7
8
Even : 22  
Even : 20  
Odd  : 9  
Odd  : 7  
Even : 8

Explanation

Value	Condition	Result
22	22 % 2 == 0 - true	Even
20	20 % 2 == 0 - true	Even
9	9 % 2 == 1 - true	Odd
7	7 % 2 == 1 - true	Odd
8	8 % 2 == 0 - true	Even

Key Point

% is the modulus operator used to get the remainder.

The logic applies to both positive and negative integers.

Ideal for practicing control structures and arrays.